You can change these however you need.įor example, if I wanted to solve: Σ π*i^2įor a sequence I, I could do the following: reduce(lambda a, x: a + 3.14*x*x, +) The sequence we are summing is represented by the iterable. The formula to the right of the sigma is represented by the lambda. The current value in the iterable is set to x and added to the accumulator. The accumulator is a and is set to the first value ( 0), and then the current sum following that. Reduce() will take arguments of a callable and an iterable, and return one value as specified by the callable. Result = reduce(lambda a, x: a + x, +list(range(1,3+1)))
You can use the following: from functools import reduce Sum(0.75 ** i for i, si in enumerate(parts))Īn efficient way to do this in Python is to use reduce(). Sum(0.75 ** i * si for i, si in enumerate(parts)) The head will thus always determine at least 25% of the speedįor example, suppose the shell has a Composite Head (speed modifierġ.6), a Solid Warhead Body (speed modifier 1.3), and a Supercavitationįrom the example we can see that i starts from 0 not the usual 1 and so we can do def speed_coefficient(parts): Weighted average of the speed modifiers s i of the (non-Ĭasing) parts, where each component i starting at the head has half the In Python, sum will take the sum of a range, and you can write the expression as a comprehension:Ī factor in muzzle velocity is the speed coefficient, which is a
Captial sigma (Σ) applies the expression after it to all members of a range and then sums the results.
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